(c) $\tan\theta = \frac{v^{2}}{rg}$ $\therefore\theta = \tan^{- 1}\left( \frac{v^{2}}{rg} \right) = \tan^{- 1}\left( \frac{10 \times 10}{10 \times 10} \right)$ $\therefore\theta = \tan^{- 1}{(1) = 45{^\circ}}$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.