(b) From, $\tan{\theta = \frac{v^{2}}{rg}}$ $r = \frac{v^{2}}{g\tan\theta} = \frac{10 \times 10}{10 \times \tan{45{^\circ}}} = 10\ m$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.