Q. Radius of the curved road on national highway is $R.$ Width of the road is $b.$ The outer edge of the road is raised by $h$ with respect to inner edge so that a car with velocity $v$ can pass safe over it. The value of $h$ is
A) $\frac{v^{2}b}{Rg}$
B) $\frac{v}{Rgb}$
C) $\frac{v^{2}R}{g}$
D) $\frac{v^{2}b}{R}$
Explanation
(a) We know that $\tan\theta = \frac{v^{2}}{Rg}$ and ${tan\ \theta}\begin{array}{r}
= \frac{h}{b} \\
\
\end{array}$
Hence $\frac{h}{b} = \frac{v^{2}}{Rg} \Rightarrow h = \frac{v^{2}b}{Rg\ }$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.