(a) Max. tension that string can bear $= 3.7\ kgwt = 37\ N$
Tension at lowest point of vertical loop $= mg + m\omega^{2}r$
$= 0.5 \times 10 + 0.5 \times \omega^{2} \times 4 = 5 + 2\omega^{2}$
$\therefore 37 = 5 + 2\omega^{2} \Rightarrow \omega = 4\ rad/s$