Q. A ball is projected up an incline of $30{^\circ}$ with a velocity of $30\ ms^{- 1}$ at an angle of $30{^\circ}$ with reference to the inclined plane from the bottom of the inclined plane. If $g = 10ms^{- 2}$, then the range on the inclined plane is
A) 12 m
B) 60 m
C) 120 m
D) 600 m
Explanation
(b) $R = \frac{2 \times 30 \times 30\sin{30{^\circ}}\cos{60{^\circ}}}{10\cos^{2}{30{^\circ}}}$
$= 180 \times \frac{1}{2} \times \frac{1}{2} \times \frac{2 \times 2}{3}m = 60\ m$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.