Q. A body is moving in a circular path with acceleration $a$. If its velocity gets doubled, find the ratio of acceleration after and before the change

A) $1\ :4$
B) $\frac{1}{4}:2$
C) $2\ :1$
D) $4\ :1$
Explanation

(d) In a circular motion
$a = \frac{v^{2}}{r} \Rightarrow \frac{a_{2}}{a_{1}} = \left( \frac{v_{2}}{v_{1}} \right)^{2} = \left( \frac{2v_{1}}{v_{1}} \right)^{2} = 4$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.