(c) $Given,\ m = 500\ kg,$ $v = 36\ {kmh}^{- 1} = 36 \times \frac{5}{18} = 10{\ \ ms}^{- 1}\ and\ r = 50\ m$ $Centripetal\ force\ F = \frac{{mv}^{2}}{r}$ $Hence,\ \ \ F = \frac{500 \times {(10)}^{2}}{50} = 1000\ N$
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Ph.D. in Physics with 19+ years of teaching experience.