Q. What is the angle between $\overrightarrow{P}$ and $\overrightarrow{Q}$. The resultant of $(\overrightarrow{P} + \overrightarrow{Q})$ and ($\overrightarrow{P} - \overrightarrow{Q}$)?

A) Zero
B) $\tan^{- 1}{(P/Q)}$
C) $\tan^{- 1}{(Q/P)}$
D) $\tan^{- 1}{(P - Q)/(P + Q)}$
Explanation

(a) Resultant $\overrightarrow{R} = \left( \overrightarrow{P} + \overrightarrow{Q} \right) + \left( \overrightarrow{P} - \overrightarrow{Q} \right) = 2\overrightarrow{P}$. Thus angle between $\overrightarrow{R}$ and $\overrightarrow{P}\ \ $ is 0${^\circ}$.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.