A stone of mass 1 kg tied to the end of a string of length 1 m, is whirled in a horizontal circle with a uniform angular velocity 2 ${rads}^{- 1}$. The tension of the string is (in newton)

Question

Dr. Abubacker · Accepted Answer

(c) The tension of the string,
$T = mr\omega^{2}$
$= 1 	imes 1 	imes {(2)}^{2} = 4N$

Q. A stone of mass 1 kg tied to the end of a string of length 1 m, is whirled in a horizontal circle with a uniform angular velocity 2 ${rads}^{- 1}$. The tension of the string is (in newton)

Explanation

Reviewed by Dr. Abubacker

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