Q. A body is projected at an angle $\theta$ with respect to horizontal direction with velocity $u.$ The maximum range of the body is

A) $R = \frac{u^{2}\sin{2\theta}}{g}$
B) $R = \frac{u^{2}\sin^{2}\ \theta}{2g}$
C) $R = \frac{u^{2}}{g}$
D) $R = u^{2}\sin\theta$
Explanation

(c) $R = \frac{u^{2}sin2\theta}{g},\ At\ \theta = 45{^\circ},\ R = max.$
$\therefore\ \ R_{\max} = \frac{u^{2}}{g}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.