Q. A bucket filled with water is tied to a rope of length 0.5 m and is rotated in a circular path in vertical pane. The least velocity it should have at the lowest point of circle so that water dose not spill is, $(g = {10\ ms}^{- 2})$
A) $\sqrt{5}\ {\ ms}^{- 1}$
B) $\sqrt{10}\ {\ ms}^{- 1}$
C) $5\ {\ ms}^{- 1}$
D) $2\sqrt{5}\ {\ ms}^{- 1}$
Explanation
(c) For water not to spill out of the bucket,
$v_{\min} = \sqrt{5gR}$ (at the lowest point)
$= \sqrt{5 \times 10 \times 0.5 = 5\ {ms}^{- 1}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.