The bob of a pendulum of mass $m$ and length $L$ is displaced, $90{^\circ}$ from the vertical and gently released. In order that the string may not break upon passing through the lowest point, its minimum strength must be

Question

Dr. Abubacker · Accepted Answer

(c) If $v$ is velocity of the bob on reaching the lowest point, then $\frac{1}{2}mv^{2} = mgL$
To void breaking, strength of the string
$T_{L} = \frac{mv^{2}}{L} + mg = \frac{2mg\ L}{L} + mg = 3\ mg$

Q. The bob of a pendulum of mass $m$ and length $L$ is displaced, $90{^\circ}$ from the vertical and gently released. In order that the string may not break upon passing through the lowest point, its minimum strength must be

Explanation

Reviewed by Dr. Abubacker

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