Q. If $\overrightarrow{A}$=$2\widehat{i} + 3\widehat{j} + 4\widehat{k}$ and $\overrightarrow{B} = 4\widehat{i} + 3\widehat{j} + 2\widehat{k}$, then angle between $\overrightarrow{A}$ and $\overrightarrow{B}$ is
A) $\sin^{- 1}{(25/29)}$
B) $\sin^{- 1}{(29/25)}$
C) $\cos^{- 1}{(25/29)}$
D) $\cos^{- 1}{(29/25)}$
Explanation
(c) cos$\theta = \overrightarrow{A} \bullet \overrightarrow{B}/AB$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.