Q. An aeroplane flying horizontally with a speed of $360\ kmh^{- 1}$ releases a bomb at a height of 490 m from the ground. When will the bomb strike the ground?
A) 8 s
B) 6 s
C) 7 s
D) 10 s
Explanation
(d) $t = \sqrt{\frac{2 \times 490}{9.8}} = \sqrt{\frac{2 \times 49 \times 100}{98}} = \sqrt{100}\ s = 10\ s$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.