(d) Here, $h = 1\ m,r = 100\ m,2x = 1.5\ m$ For no skidding $\frac{mv^{2}}{r} \times h = mg\ x$ $v = \sqrt{\frac{g\ r\ x}{h}} = \sqrt{\frac{9.8 \times 100 \times 0.75}{1}}$ $v = 27.1\ ms^{- 1}$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.