Q. A particle of mass $m$ moves with constant speed along a circular path of radius $r$ under the action of a force $F.$ Its speed is
A) $\sqrt{\frac{rF}{m}}$
B) $\sqrt{\frac{F}{r}}$
C) $\sqrt{Fmr}$
D) $\sqrt{\frac{F}{mr}}$
Explanation
(a) $F = \frac{mv^{2}}{r}\ \Rightarrow v = \ \sqrt{\frac{rF}{m}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.