Q. An aeroplane moving horizontally at a speed of $200\ ms^{- 1}$ and at a height of $8 \times 10^{3}m$ is to drop a bomb on a target. At what horizontal distance from the target should the bomb be released? (Take $g = 10\ ms^{- 2}$)

A) 9124 m
B) 8714 m
C) 8000 m
D) 7234 m
Explanation

(c) $t = \sqrt{\frac{2 \times 8 \times 10^{3}}{10}} = 40\ s$
$x = vt = 200 \times 40 = 8000m$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.