Q. A car of mass 1000 kg negotiates a banked curve of radius $90\ m$ on a frictionless road. If the banking angle is $45{^\circ}$, the speed of the car is
A) $20ms^{- 1}$
B) $30ms^{- 1}$
C) $5ms^{- 1}$
D) $10ms^{- 1}$
Explanation
(b) For banking $\tan\theta = \frac{V^{2}}{Rg}$
$\tan 45 = \frac{V^{2}}{90 \times 10} = 1$
$V = 30\ m/s$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.