Q. Two bodies are projected from ground with equal speeds $20\ m/sec$ from the same position in same vertical plane to have equal range but at different angle above the horizontal. If one of the angle is $30{^\circ}$ the sum of their maximum heights is (assume $g = 10m/s^{2})$

A) $400\ m$
B) $20\ m$
C) $30\ m$
D) $40\ m$
Explanation

(b) $H_{1} + H_{2} = \frac{u^{2}}{2g}(\sin^{2}{30{^\circ}} + \sin^{2}{60{^\circ}})$
$= \frac{20^{2}}{2 \times 10}\left( \frac{1}{4} + \frac{3}{4} \right) = 20\ m$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.