Q. A body moves along a circular path of radius 5 m. The coefficient of friction between the surface of path and the body is 0.5. The angular velocity, in radians/sec, with which the body should move so that it does not leave the path is $(g = 10ms^{- 2})$
A) 4
B) 3
C) 2
D) 1
Explanation
(d) Here, $r = 5\ m,\mu = 0.5,\omega = ?,g = 10ms^{- 2}$
$mr\omega^{2} = F = \mu R = \mu\ mg$
$\omega = \sqrt{\frac{\mu g}{r}} = \sqrt{\frac{0.5 \times 10}{5}} = 1\ $rad $s^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.