Q. A particle moves along the parabolic path $y = ax^{2}$ in such a way that the $x$-component of the velocity remains constant, say $c$. The acceleration of the particle is
A) $ac\widehat{\mathbf{k}}$
B) $2ac^{2}\widehat{\mathbf{j}}$
C) $ac^{2}\widehat{\mathbf{k}}$
D) $a^{2}c\widehat{\mathbf{j}}$
Explanation
The correct answer is Option B: $2ac^{2}\widehat{\mathbf{j}}$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.