Q. A particle is moving on a circular path of radius $r$ with uniform velocity $v$. The change in velocity when the particle moves from $P\ $to$\ Q\ $is$\ (\angle POQ = 40{^\circ})$
A) $2v\cos{40{^\circ}}$
B) $2v\sin{40{^\circ}}$
C) $2v\sin{20{^\circ}}$
D) $2v\cos{20{^\circ}}$
Explanation
(c) Change in velocity $= 2v\sin{(\theta/2) = 2v\sin{20{^\circ}}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.