Q. The horizontal range of a projectile is $4\sqrt{3}$ times its maximum height. Its angle of projection will be
A) $45{^\circ}$
B) $60{^\circ}$
C) $90{^\circ}$
D) $30{^\circ}$
Explanation
(d) $R = 4H\cot\theta,$ if $R = 4\sqrt{3}H$ then $\cot\theta = \sqrt{3} \Rightarrow \theta = 30{^\circ}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.