Q.
The resultant of a system of forces shown in figure is a force of 10 N parallel to given forces through $R$, where $PR$ equals
A) (2/5)$R\ \ Q$
B) (3/5)$R\ \ Q$
C) (2/3)$R\ \ Q$
D) (1/2)$R\ \ Q$
Explanation
(c) Equating the moments about $R$
$6 \times PR = 4 \times RQ$
$PR = \frac{4}{6}RQ = \frac{2}{3}RQ$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.