(b) Area in which bullet will spread $= \pi r^{2}$
For maximum area, $r = R_{\max} = \frac{v^{2}}{g}\ \lbrack When\ \theta = 45{^\circ}\rbrack$
Maximum area $\pi R_{\max}^{2} = \pi\left( \frac{\upsilon^{2}}{g} \right)^{2} = \frac{{\pi\upsilon}^{4}}{g^{2}}$