Q. An electric fan has blades of length $30\ cm$ as measured from the axis of rotation. If the fan is rotating at $1200\ r.p.m.$The acceleration of a point on the tip of the blade is about
A) $1600\ m/\sec^{2}\ $
B) $4740\ m/\sec^{2}\ $
C) $2370\ m/\sec^{2}\ $
D) $5055\ m/\sec^{2}\ $
Explanation
(b) $\omega^{2}R = 4\pi^{2}n^{2}r = 4\pi^{2}\left( \begin{array}{r}
\frac{1200}{60} \\
\
\end{array} \right)^{2} \times 30 \times 10^{- 2} = 4732\ m/s^{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.