Q. A car of mass $800\ kg\ $moves on a circular track of radius $40\ m$. If the coefficient of friction is 0.5, then maximum velocity with which the car can move is
A) $7\ m/s$
B) $14\ m/s$
C) $8\ m/s$
D) $12\ m/s$
Explanation
(b) $v_{\max} = \sqrt{\mu rg} = \sqrt{0.5 \times 40 \times 9.8} = 14\ m/s$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.