Q. Ratio between maximum range and square of time of flight in projectile motion is
A) $10\ :49$
B) $49\ :10$
C) $98\ :10$
D) $10\ :98$
Explanation
(b) For maximum range $\theta = 45{^\circ}$
$\frac{R_{\max}}{T^{2}} = \frac{\frac{u^{2}\sin{2\theta}}{g}\ }{\frac{{4u}^{2}\sin^{2}\theta}{g^{2}}}$
$\Rightarrow \frac{R_{\max}}{T^{2}} = \frac{\sin{90{^\circ} \times g}}{4 \times \sin^{2}{45{^\circ}}} = \frac{49}{10}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.