Q. The speed of revolution of a particle going around a circle is doubled and its angular speed is halved. What happens to the centripetal acceleration?
A) Becomes four times
B) Double
C) Halved
D) Remains unchanged
Explanation
(d) $r_{1} = v/\omega;$ $r_{2} = 2v/(\omega/2) = 4v/\omega = 4r_{1}$
$a_{1} = v^{2}/r_{1};a_{2} = (2v)^{2}/r_{2} = 4v^{2}/r_{1} = v^{2}/r_{1} = a_{1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.