Q. A body of mass $1\ kg$ tied to one end of string is revolved in a horizontal circle of radius $0.1\ m$ with a speed of $3\ revolution/sec$, assuming the effect of gravity is negligible, then linear velocity, acceleration and tension in the string will be
A) $1.88\ m/s,35.5m/s^{2},\ 35.5\ N$
B) $2.88\ m/s,45.5m/s^{2},\ 45.5\ N$
C) $3.88\ m/s,55.5m/s^{2},\ 55.5\ N$
D) None of these
Explanation
(a) Linear velocity,
$v = \omega r = 2\pi nr = 2 \times 3.14 \times 3 \times 0.1 = 1.88\ m/s$
Acceleration, $a = \omega^{2}r = (6\pi)^{2} \times 0.1 = 35.5\ m/s^{2}$
Tension in string, $T = m\omega^{2}r = 1 \times (6\pi)^{2} \times 0.1 = 35.5\ N$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.