Q. For a particle in uniform circular motion, thee acceleration $\overrightarrow{a}$ at a point $P(R,\theta)$ on the circle of radius R is (Here $\theta$ is measured from the x-axis)
A) $\frac{v^{2}}{R}\widehat{i} + \frac{v^{2}}{R}\widehat{j}$
B) $- \frac{v^{2}}{R}\cos\theta\widehat{i} + \frac{v^{2}}{R}\sin\theta\widehat{j}$
C) $- \frac{v^{2}}{R}\sin\theta\widehat{i} + \frac{v^{2}}{R}\cos\theta\widehat{j}$
D) $- \frac{v^{2}}{R}\cos\theta\widehat{i} - \frac{v^{2}}{R}\sin\theta\widehat{j}$
Explanation
(d) [image:4_image98.emf]
$\overrightarrow{a} = - \frac{v^{2}}{R}\cos{\theta\widehat{i}} - \frac{v^{2}}{R}\sin{\theta\widehat{j}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.