Q. The tension in the string revolving in a vertical circle with a mass $m$ at the end which is the lowest position
A) $\frac{mv^{2}}{r}$
B) $\frac{mv^{2}}{r} - mg$
C) $\frac{mv^{2}}{r} + mg$
D) $mg$
Explanation
(c) Tension = Centrifugal force + weight $= \frac{mv^{2}}{r} + mg$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.