A man standing on the roof of a house of height $h$ throws one particle vertically downwards and another particle horizontally with the same velocity $u$. The ratio of their velocities when they reach the earth’s surface will be

Question

Dr. Abubacker · Accepted Answer

(c) When a particle is thrown in vertical downward direction with velocity $u$ then final velocity at the ground level
$v^{2} = u^{2} + 2gh\ 	herefore v = \sqrt{u^{2} + 2gh}$
Another particle is thrown horizontally with same vertically then at the surface of earth
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Horizontal component of velocity $v_{x} = u$
$	herefore$ Resultant velocity, $v = \sqrt{u^{2} + 2gh}$
For both the particle final velocities when they reach the earth’s surface are equal

Q. A man standing on the roof of a house of height $h$ throws one particle vertically downwards and another particle horizontally with the same velocity $u$. The ratio of their velocities when they reach the earth’s surface will be

Explanation

Reviewed by Dr. Abubacker

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