Q. If a car is to travel with a speed $v$ along the frictionless, banked circular track of radius $r$, the required angle of banking so that the car does skid is
A) $\theta = \tan^{- 1}\left( \frac{v^{2}}{rg} \right)$
B) $\theta = \tan^{- 1}\left( \frac{v}{rg} \right)$
C) $\theta = \tan^{- 1}\left( \frac{r^{2}}{vg} \right)$
D) $\theta < \tan^{- 1}\left( \frac{v^{2}}{rg} \right)$
Explanation
The correct answer is Option D: $\theta < \tan^{- 1}\left( \frac{v^{2}}{rg} \right)$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.