Q.
A body of mass $m$ is moving with a uniform speed $v$ along a circle of radius $r$, what is the average acceleration in going from $A$ to $B$?
A) $2v^{2}/\pi r$
B) $2\sqrt{2}v^{2}/\pi r$
C) $v^{2}/\pi r$
D) None of these
Explanation
(b) Here, $T = \frac{2\pi r}{4v} = \frac{\pi r}{2v}$
Change in velocity is going from $A$ to $B$ = $v\sqrt{2}$
Average acceleration $= \frac{\ v\sqrt{2}}{\pi r/2v} = \frac{2\ \sqrt{2}v^{2}}{\pi r}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.