(c) $T = \frac{2 \times 50 \times \frac{1}{2}}{10} = 5\ s$ Horizontal distance travelled in last 2 s $= 50 \times \cos{30{^\circ}} \times 2\ m$ $= 100 \times \frac{2}{\sqrt{3}}m = 50\sqrt{3}m = 86.6\ m$
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Ph.D. in Physics with 19+ years of teaching experience.