(d) Tension at mean position, $mg + \frac{mv^{2}}{l} = 3mg$
$v = \sqrt{2gl}$
And if the body displaces by angle $\theta$ with the vertical
Then $v = \sqrt{2gl(1 - \cos\theta)}$
Comparing (i) and (ii), $\cos{\theta = 0 \Rightarrow \theta = 90{^\circ}}$