Q. If KE of the particle of mass $m$ performing UCM in a circle of radius $r$ is E. Find the acceleration of the particale
A) $\frac{2E}{mr}$
B) $\left( \frac{2E}{mr} \right)^{2}$
C) $2\ Emr$
D) $\frac{4E}{mr}$
Explanation
(a) Kinetic energy
$E = \frac{1}{2}{mv}^{2}$
$or\ \frac{1}{2}mr\frac{v^{2}}{r} = E$
$or\ \frac{1}{2}mra = E$
$or\ \ a = \frac{2E}{mr}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.