Q. A bullet is fired from a cannon with velocity $500\ m/s$ . If the angle of projection is $15{^\circ}$ and $g = 10\ m/s^{2}$. Then the range is
A) $25 \times 10^{3}\ m$
B) $12.5 \times 10^{3}\ m$
C) $50 \times 10^{2}\ m$
D) $25 \times 10^{2}\ m$
Explanation
(b) $R = \frac{u^{2}\sin{2\theta}}{g} = \frac{(500)^{2} \times \sin{30{^\circ}}}{10} = 12.5 \times 10^{3}\ m$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.