Q. A body is thrown with a velocity of $9.8\ m/s$ making an angle of $30{^\circ}$ with the horizontal. It will hit the ground after a time
A) $1.5\ s$
B) $1\ s$
C) $3\ s$
D) $2\ s$
Explanation
(b) $T = \frac{2u\sin\theta}{g} = \frac{2 \times 9.8 \times \sin 30}{9.8} = 1\ s$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.