Q. A ball is projected with kinetic energy $K$ at an angle of $45{^\circ}$ to the horizontal. At the highest point during its flight, its kinetic energy will be
A) $K$
B) $K/\sqrt{2}$
C) $K/2$
D) Zero
Explanation
(c) Kinetic energy at highest point$= K\cos^{2}{45{^\circ}} = \frac{K}{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.