(c) Here, $v = 900\ km{\ h}^{- 1} = \frac{900 \times 1000}{60 \times 60} = 250\ ms^{- 1}$ $g = 9.8\ ms^{- 2}$ For apparent weightlessness, $\frac{mv^{2}}{r} = mg$ $r = \frac{v^{2}}{g} = \frac{250 \times 250}{9.8}$ $= 6377.5\ m = 6.4\ km$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.