An aeroplane flying at a velocity of 900 $kmh^{- 1}$ loops the loop. If the maximum force pressing the pilot against the seat is five times its weight, the loop radius should be

Question

Dr. Abubacker · Accepted Answer

(a) Here, $v = 900\ km{\ h}^{- 1}$
$= \frac{900 	imes 1000}{60 	imes 60}ms^{- 1} = 250\ ms^{- 1}$
Minimum force is at the bottom of the vertical circle
$F_{\max} = \frac{mv^{2}}{r} + mg = 5\ mg$
$	herefore\ v^{2} = 4\ gr$
or $r = \frac{v^{2}}{4g} = \frac{250 	imes 250}{4 	imes 980} = 1594$ m

Q. An aeroplane flying at a velocity of 900 $kmh^{- 1}$ loops the loop. If the maximum force pressing the pilot against the seat is five times its weight, the loop radius should be

Explanation

Reviewed by Dr. Abubacker

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