Q. A body is thrown upward from the earth surface with velocity $5\ m/s$ and from a planet surface with velocity $3\ m/s$. Both follow the same path. What is the projectile acceleration due to gravity on the planet
A) $2\ m/s^{2}$
B) $3.5\ m/s^{2}$
C) $4\ m/s^{2}$
D) $5\ m/s^{2}$
Explanation
(b) $\upsilon^{2} = u^{2} + 2as$
At max. height $\upsilon = 0$ and for upward direction $a = - g$
$\therefore u^{2} = 2gs \Rightarrow s = \frac{u^{2}}{2g};\ \because s_{e} = s_{p}$
$\left( \frac{u_{e}}{u_{p}} \right)^{2} = \left( \frac{g_{e}}{g_{p}} \right) \Rightarrow \left( \frac{5}{3} \right)^{2} = \frac{9.8}{g_{p}} \Rightarrow g_{p} = 3.5\ m/s^{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.