Q. Two forces, each equal to $\frac{P}{2}$, act at right angles. Their effect may be neutralized by a third force acting along their bisector in the opposite direction with a magnitude of
A) $P$
B) $\frac{P}{2}$
C) $\frac{P}{\sqrt{2}}$
D) $\sqrt{2}\ P$
Explanation
(c) $F = \sqrt{\left( \frac{P}{2} \right)^{2} + \left( \frac{P}{2} \right)^{2}} = \sqrt{2\ }\ \frac{P}{2} = \frac{P}{\sqrt{2\ }}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.