The sum of the magnitudes of two forces acting at a point is 16 N. the resultant of these forces is perpendicular to the smaller force has a magnitude of 8 N. If the smaller force is magnitude $x$, then the value of $x$ is

Question

Dr. Abubacker · Accepted Answer

(c) $x + y = 16,$ Also $y^{2} = 8^{2} + x^{2}$
or $y^{2} = 64 + (16 - y)^{2}$
$\lbrack\because\ \ x = 16 - ybrack$
or $y^{2} = 64 + 256 + y^{2} - 32y$
or $32y = 320$ or $y = 10$N
$	herefore\ \ x + 10 = 16$ or $x = 6$N
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Q. The sum of the magnitudes of two forces acting at a point is 16 N. the resultant of these forces is perpendicular to the smaller force has a magnitude of 8 N. If the smaller force is magnitude $x$, then the value of $x$ is

Explanation

Reviewed by Dr. Abubacker

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