Q. A particle of mass $m\ $is executing uniform circular motion on a path of radius $r.$ If $p$ is the magnitude of its linear momentum. The radial force acting on the particle is
A) $pmr$
B) $\frac{rm}{p}$
C) $\frac{mp^{2}}{r}$
D) $\frac{p^{2}}{rm}$
Explanation
(d) Radial force $= \frac{mv^{2}}{r} = \frac{m}{r}\left( \frac{p}{m} \right)^{2} = \frac{p^{2}}{mr}$[As $p = mv$]
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.