Q. Given $\overrightarrow{A} = \widehat{i} + 2\widehat{j} - 3\widehat{k}$. When a vector $\overrightarrow{B}$ is added to $\overrightarrow{A}$, We get a unit vector along $X$=axis. Then, $\overrightarrow{B}$ is
A) $- 2\widehat{j} + 3\widehat{k}$
B) $- \widehat{i} - 2\widehat{j}$
C) $- \widehat{i} + 3\widehat{k}$
D) $2\widehat{j} - 3\widehat{k}$
Explanation
(a) $\overrightarrow{B} + \left( \widehat{i} + 2\widehat{j} - 3\widehat{k} \right) = \widehat{i}$
or $\overrightarrow{B} =$ $- 2\widehat{j} + 3\widehat{k}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.