Q. If the angle of projection of a projectile is $30{^\circ}$, then how many times the horizontal range is larger than the maximum height?
A) 2
B) 3
C) $3\sqrt{4}$
D) $4\sqrt{3}$
Explanation
(d) $\theta = 30{^\circ}$
$\frac{R}{H} = \frac{v^{2}(2\sin\theta\cos\theta)}{g} \times \frac{2g}{v^{2}\sin^{2}\theta} = \frac{4\cos\theta}{\sin\theta}$
or $R = 4\cot{30{^\circ}} \times H = 4\sqrt{3}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.