Q. Two bodies are projected with the same velocity. If one is projected at an angle of $30{^\circ}$ and the other at an angle of $60{^\circ}$ to the horizontal, the ratio of the maximum heights reached is
A) $3\ :1$
B) $1\ :3$
C) $1\ :2$
D) $2\ :1$
Explanation
(b) As $H = \frac{u^{2}\sin^{2}\theta}{2g}\ \therefore\frac{H_{1}}{H_{2}} = \frac{\sin^{2}\theta_{1}}{\sin\theta_{2}} = \frac{\sin^{2}{30{^\circ}}}{\sin^{2}60} = \frac{1/4}{3/4} = \frac{1}{3}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.